10x^2-(2/8)x=0

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Solution for 10x^2-(2/8)x=0 equation: 


x in (-oo:+oo)

10*x^2-((2/8)*x) = 0

10*x^2+(-1/4)*x = 0

10*x^2-1/4*x = 0

DELTA = (-1/4)^2-(0*4*10)

DELTA = 1/16

DELTA > 0

x = ((1/16)^(1/2)+1/4)/(2*10) or x = (1/4-(1/16)^(1/2))/(2*10)

x = 1/40 or x = 0

x in { 0, 1/40 }

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